Re: [nbos] [AS] Travel Times
Alan Bartholet
Sat Aug 29th, 2009
Hello Anthony,
You are correct I missed the part about this being for interstellar
travel, I was thinking Interplanetary. I should really be in bed
right now ;)

Best Regards,
Alan Bartholet

On Fri, Aug 28, 2009 at 11:41 PM, Antony Farrell<skaran-at-bordernet.com.au> wrote:
> Actually things are going to get a lot more complicated because with a drive
> capable of sustained acceleration you are going to run into lightspeed
> problems or out of Newtonian physics.
>
> Personally I would set a maximum velocity, say 0.1 times the speed of
> light, ignore the aceeleration and deceleration times since they will be
> largely insignificant compared to the overall journey. So from Sol to Alpha
> Centauri about 43 years, to 61 Cygni at about 11.3 light years distance
> around 113 years etc. Constant acceleration builds up fast so would as I
> said not add a great deal of transit time.
>
> Antony
>
>> -----Original Message-----
>> From: nbossoftware-bounces-at-nbos.com
>> [mailto:nbossoftware-bounces-at-nbos.com] On Behalf Of Alan Bartholet
>> Sent: Saturday, 29 August 2009 1:16 PM
>> To: nbossoftware-at-nbos.com
>> Subject: Re: [nbos] [AS] Travel Times
>>
>>
>> Hello Doug,
>>    If you are using some form of reactionless thrust drive,
>> allowing for continuous acceleration, then you can calculate
>> the travel time with the following formula:
>>
>> T = 68 * [square root of [D/A])
>> -------------------------------------------
>> T  = time in hours
>> D = distance in AU.
>> A = spacecraft's acceleration in G.
>>
>> If your using a reaction drive then things get a little more
>> complex. First you need to calculate the time required to
>> accelerate to the cursing speed:
>>
>> T = dV * 0.0455/A
>> ---------------------------
>> T = time in hours.
>> dV = the total delta- V required for the acceleration.
>> A = the spacecraft's acceleration in G.
>>
>> It is easiest to assume that the space ship will spend the
>> same amount of time deceleration.
>>
>> Then you need to calculate the distance covered during your
>> acceleration to the cursing speed:
>>
>> cD = T^2 * A * 0.00042
>> --------------------------------
>> cD  = distance travelled in AU during constant acceleration. T =
>> acceleration time in hours as previously calculated. A = acceleration
>> in G.
>>
>> It is easiest to assume that distance travelled while
>> decelerating is the same.
>>
>> Then you need to calculate the distance travelled while cursing:
>>
>> Time spent cruising (days) = (tD - (cD * 2)) * 1076/dV
>> ---------------------------------------------------------------
>> tD = distance to the destination in astronomical units (AU) cD =
>> distance travelled during accelerating (we multiply it by 2 to account
>> for decelerating as well). dV  = cruising
>> delta- V in mps.
>>
>> So the total travel time would be:
>>
>> Total travel time (days) = Time spent cursing (days) + (Time spent
>> accelerating/24)
>>
>> Both of these do not take into account time dilation but
>> until you reach around 1/4c the affects are not worth taking
>> into account.
>>
>> I hope this helps.
>>
>> Best Regards,
>>    Alan Bartholet
>>
>> On Fri, Aug 28, 2009 at 7:38 PM, Doug
>> Jessee<ldjessee-at-gmail.com> wrote:
>> > Hello,
>> >
>> > I am trying to figure out some travel times at slower than light.
>> >
>> > Anyone know of any easy way to compute these times?
>> >
>> > For example, a sleeper ship that is going from earth to 61 Cygni.
>> > Assuming acceleration of 3/4 Gs, I was just trying to
>> figure out how
>> > long it would take to travel.
>> >
>> > -Doug Jessee
>> >
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>> >
>> >
>> >
>> >
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