Re: [nbos] [AS] Travel Times"Antony Farrell" Sat Aug 29th, 2009Actually things are going to get a lot more complicated because with a drive

capable of sustained acceleration you are going to run into lightspeed

problems or out of Newtonian physics.

Personally I would set a maximum velocity, say 0.1 times the speed of

light, ignore the aceeleration and deceleration times since they will be

largely insignificant compared to the overall journey. So from Sol to Alpha

Centauri about 43 years, to 61 Cygni at about 11.3 light years distance

around 113 years etc. Constant acceleration builds up fast so would as I

said not add a great deal of transit time.

Antony

> -----Original Message-----

> From: nbossoftware-bounces-at-nbos.com

> [mailto:nbossoftware-bounces-at-nbos.com] On Behalf Of Alan Bartholet

> Sent: Saturday, 29 August 2009 1:16 PM

> To: nbossoftware-at-nbos.com

> Subject: Re: [nbos] [AS] Travel Times

>

>

> Hello Doug,

> If you are using some form of reactionless thrust drive,

> allowing for continuous acceleration, then you can calculate

> the travel time with the following formula:

>

> T = 68 * [square root of [D/A])

> -------------------------------------------

> T = time in hours

> D = distance in AU.

> A = spacecraft's acceleration in G.

>

> If your using a reaction drive then things get a little more

> complex. First you need to calculate the time required to

> accelerate to the cursing speed:

>

> T = dV * 0.0455/A

> ---------------------------

> T = time in hours.

> dV = the total delta- V required for the acceleration.

> A = the spacecraft's acceleration in G.

>

> It is easiest to assume that the space ship will spend the

> same amount of time deceleration.

>

> Then you need to calculate the distance covered during your

> acceleration to the cursing speed:

>

> cD = T^2 * A * 0.00042

> --------------------------------

> cD = distance travelled in AU during constant acceleration. T =

> acceleration time in hours as previously calculated. A = acceleration

> in G.

>

> It is easiest to assume that distance travelled while

> decelerating is the same.

>

> Then you need to calculate the distance travelled while cursing:

>

> Time spent cruising (days) = (tD - (cD * 2)) * 1076/dV

> ---------------------------------------------------------------

> tD = distance to the destination in astronomical units (AU) cD =

> distance travelled during accelerating (we multiply it by 2 to account

> for decelerating as well). dV = cruising

> delta- V in mps.

>

> So the total travel time would be:

>

> Total travel time (days) = Time spent cursing (days) + (Time spent

> accelerating/24)

>

> Both of these do not take into account time dilation but

> until you reach around 1/4c the affects are not worth taking

> into account.

>

> I hope this helps.

>

> Best Regards,

> Alan Bartholet

>

> On Fri, Aug 28, 2009 at 7:38 PM, Doug

> Jessee<ldjessee-at-gmail.com> wrote:

> > Hello,

> >

> > I am trying to figure out some travel times at slower than light.

> >

> > Anyone know of any easy way to compute these times?

> >

> > For example, a sleeper ship that is going from earth to 61 Cygni.

> > Assuming acceleration of 3/4 Gs, I was just trying to

> figure out how

> > long it would take to travel.

> >

> > -Doug Jessee

> >

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> >

> >

> >

> >

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